Union of Events: A,B,C... - 65 Characters

  • Thread starter Thread starter r0bHadz
  • Start date Start date
  • Tags Tags
    Events Union
Click For Summary

Homework Help Overview

The discussion revolves around the concept of the union of events in probability theory, specifically addressing the definition and implications of this concept. Participants explore the meaning of a union of events A, B, C, etc., and how it relates to outcomes occurring in these events.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the definition of a union of events, questioning whether it implies that all events must occur or if any single event suffices. Some attempt to rationalize the definition through examples and analogies, while others clarify the distinction between union and intersection operations.

Discussion Status

The discussion is active, with participants sharing their interpretations and examples to clarify the concept. Some guidance has been offered regarding the mathematical definition of union, and there is acknowledgment of the need to accept this definition for effective communication in mathematics.

Contextual Notes

Participants note the potential for misunderstanding due to the use of everyday language versus mathematical terminology. There is also mention of specific examples involving sets of students and outcomes from rolling a die to illustrate the concept further.

r0bHadz
Messages
194
Reaction score
17

Homework Statement


Definition:

A union of events A,B,C, . . . is an event consisting of all the outcomes in all
these events. It occurs if any of A,B,C, . . . occurs, and therefore, corresponds
to the word “or”: A or B or C or ... (Figure 2.1a).

Homework Equations

The Attempt at a Solution


I'm confused at "It occurs if any of A,B,C, . . . occurs"

If the union of events A,B,C... is an event consisting of all outcomes in all of these events, then doesn't that imply that A and B and C and ... have to occur, not A or B or C or ..?

I understand that this is their definition and they can define it anyway they want to, but it seems off for me.

One way I can possibly rationalize this is: say x is an outcome of a union b. and x is an outcome of a but not b. Since x is an outcome of a union b, if x has occurred, the event a union b has occurred. But also the event A has occuredam I on the right track?
 
Physics news on Phys.org
r0bHadz said:
I'm confused at "It occurs if any of A,B,C, . . . occurs"

If the union of events A,B,C... is an event consisting of all outcomes in all of these events, then doesn't that imply that A and B and C and ... have to occur, not A or B or C or ..?...
am I on the right track?

No. You are thinking of the intersection operation (which, roughly, is products for sets). The Union operation in some sense is the addition operation for sets.

To understand the definition: draw a 3 circle venn diagram (kind of like the olympics rings) and shade in the first circle blue, second red, third gold. Any and all shaded area is the union of the points in those circles. The intersection is only the very dark color that is that mixture called "blue-red-gold".
 
r0bHadz said:

Homework Statement


Definition:

A union of events A,B,C, . . . is an event consisting of all the outcomes in all
these events. It occurs if any of A,B,C, . . . occurs, and therefore, corresponds
to the word “or”: A or B or C or ... (Figure 2.1a).

Homework Equations

The Attempt at a Solution


I'm confused at "It occurs if any of A,B,C, . . . occurs"

If the union of events A,B,C... is an event consisting of all outcomes in all of these events, then doesn't that imply that A and B and C and ... have to occur, not A or B or C or ..?

I understand that this is their definition and they can define it anyway they want to, but it seems off for me.

One way I can possibly rationalize this is: say x is an outcome of a union b. and x is an outcome of a but not b. Since x is an outcome of a union b, if x has occurred, the event a union b has occurred. But also the event A has occuredam I on the right track?

If A = {all the male students in a class} and B = {all the female students in a class} then A∪B = {all the students in the class}. Very likely there is no student in the class that is in both sets A and B.
 
  • Like
Likes   Reactions: r0bHadz
You clearly understand what they are trying to say about the definition. That mathematics definition of "union" is universally accepted. You should accept that for the sake of communication of mathematics rather than worrying about other possible interpritations of the English language. Accept it and move on. Save the English discussion for another day.
 
Ray Vickson said:
If A = {all the male students in a class} and B = {all the female students in a class} then A∪B = {all the students in the class}. Very likely there is no student in the class that is in both sets A and B.
Nice! this was the kind of reply I was looking for. And if we have an occurrence of the event {all the male students in a class} then we also have an occurrence of {all the male students in a class} ∪ {all the female students in the class} am i right?
 
FactChecker said:
You clearly understand what they are trying to say about the definition. That mathematics definition of "union" is universally accepted. You should accept that for the sake of communication of mathematics rather than worrying about other possible interpritations of the English language. Accept it and move on. Save the English discussion for another day.

Hmm I guess you're right. I waste too much time on insignificant things like this >.>
 
Here's an example that might help clarify what is meant by "an event." Consider a six-sided die, with sides identified by one to six spots (or "pips"). There are six possible events: 1 is rolled, 2 is rolled, ..., 6 is rolled.
We could divide these six events into two sets, with E = {an even number is rolled}, and O = {an odd number is rolled}. Each of these sets contains three events. The universal set here is U = E ∪ O, which consists of all six events. Sets E and O are disjoint, meaning that when you roll a die, it can't come up with a number that is both odd and even. Symbolically, that is E ∩ O = ∅, the empty set.

The sets list the different possible events -- they don't say anything about whether the events have occurred or not. .
 
  • Like
Likes   Reactions: r0bHadz and jim mcnamara

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K