A Real vs complex spherical harmonics for hexagonal symmetry

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The discussion centers on the comparison between real and complex spherical harmonics in the context of hexagonal symmetry and their relationship to the finite angular momentum operator Lz. It highlights that complex spherical harmonics serve as eigenvectors of Lz in position representation, while questioning the relevance of crystal symmetry in determining the effectiveness of either harmonic type. Participants explore whether one form can be deemed superior based on their mathematical properties and applications in physical systems. The conversation emphasizes the need for clarity on how these harmonics interact with symmetry considerations. Ultimately, the choice between real and complex spherical harmonics may depend on specific applications and the nature of the system being analyzed.
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Orbital analysis of magnetic anisotropy energy using second order perturbation theory for hexagonal symmetry
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Are real spherical harmonics better than complex spherical harmonics for hexagonal symmetry, which are
directly associated to a finite Lz?
 
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An eigenvector of ##L_z## in position representation is a standard complex spherical harmonic, i.e.,
$$\text{Y}_{lm}=P_{lm}[\cos(\vartheta)] \exp(\mathrm{i} m \varphi).$$
Note that in spherical coordinates the position representation of ##\hat{L}_z## reads
$$\hat{L}_z=-\mathrm{i} \hbar \partial_{\varphi}.$$
 
vanhees71 said:
An eigenvector of ##L_z## in position representation is a standard complex spherical harmonic, i.e.,
$$\text{Y}_{lm}=P_{lm}[\cos(\vartheta)] \exp(\mathrm{i} m \varphi).$$
Note that in spherical coordinates the position representation of ##\hat{L}_z## reads
$$\hat{L}_z=-\mathrm{i} \hbar \partial_{\varphi}.$$

vanhees71 said:
Is there any relation between the crystal symmetry and real/complex spherical harmonics? And is there a way to judge the superiority of one over the other?
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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