Rearranging formulas. Accelerations

[kencamarador]

If I were to solve for Aav

Δd = viΔt+1/2aavΔt^2

Vi- initial velocity
Aav is average acceleration

 

[haruspex]

No, that only works for constant acceleration. Consider a velocity-time graph. The average acceleration is the slope from the start point to finish point, while the distance traveled is the area under the curve. E.g. if you stayed put for an hour then accelerated at 10kph/s for 6 seconds you'd average 1 kph/minute but cover relatively little ground. Conversely, if accelerate for the first 6 seconds then maintain a 60kph an hour you'll have the same average acceleration but go much further.