Redox Reaction: Fe(OH)_2+ O_2 -> Fe(OH)_3 Solution

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Discussion Overview

The discussion revolves around the net redox equations for the reaction between Fe(OH)2 and O2 in a basic solution, focusing on identifying oxidation and reduction half-reactions. The scope includes homework-related problem-solving and chemical reasoning.

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation

Main Points Raised

  • One participant proposes the oxidation half-reaction as Fe(OH)2 + OH-1 → Fe(OH)3 + e-.
  • Another participant suggests that oxygen may be reduced and questions whether half a mole of oxygen could be appropriate for the reaction.
  • A subsequent post asks how to work with moles in this context and how to determine the product of the reduced oxygen.
  • One participant outlines potential half-reactions, indicating that O + H2O + e- → 2OH-1 could represent the reduction of oxygen, while noting their limited familiarity with iron chemistry.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the reduction half-reaction and the specifics of working with moles, indicating that multiple competing views remain on how to approach the problem.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the stoichiometry of oxygen and the lack of clarity on the final products of the reduction reaction.

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Homework Statement



Give the net redox equations for the following reactions which occur in base solution.
[tex]Fe(OH)_2+ O_2 \rightarrow Fe(OH)_3[/tex]

Homework Equations


none

The Attempt at a Solution


The oxidation half reaction is [tex]Fe(OH)_+OH^{-1}\rightarrow Fe(OH)_3 + e^{-}[/tex].

How do we find the reduction reaction?
 
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Possibly oxygen is being reduced. Could one-half mole of oxygen be a good fit? Work from there and see what you find.
 
How would we work with this problem using moles? How could we test of one half mole of oxygen would be "a good fit?"

How would we know what that [tex]O_2[/tex] would turn into after being reduced?
 
The most obvious half reactions might be these:

Fe(OH) sub 2 + 1OH (-1 charge) ----------> Fe(OH) sub 3 +1e

O + H2O +1e ----------------> 2OH (-1 charge)
The single "O" is used here to show one half of the oxygen diatomic molecule. Right now, I do not have access to good typesetting. Understand, too that "sub x" means subscript of x.

Someone else might like to give further or better details, since I'm not too aware of much about Iron chemistry and reactions.
 

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