Redox Reaction With Nx Nitrogen Compound

[BayernBlues]

Homework Statement

Hydroxylammonium chloride reacts with Iron(III)chloride (FeCl3) in solution to produce Iron(II)Chloride, HCL, H2O, and a compound of nitrogen. It was found that 2.0 g of iron(III) chloride reacted in this way with 31 mL of 0.200 M hydroxylammonium chloride.

Suggest a possible formula of the nitrogen compound produced.
This should be a known nitrogen compound

Homework Equations

NH3OHCl + FeCl3 ----> FeCl2 + H2O + X

The Attempt at a Solution

mole FeCl3
2g(1mole/162.2g) = 0.012 mole
mole NH3OHCl
31.0ml(1L/1000mL)(0.2 mole/L) = 0.0062 mole
FeCL3 = 0.012/0.0062 = 1.9 = 2
NH3OHCl = 0.0062/0.0062 = 1

This is the part I'm stuck at. The mol ratio is 2:1 and the compound is supposed to be N2O but I don't know how to arrive at that conclusion.

 

[Borek]

You are OK so far. The only approach I can think off now is to use the information known at this stage (ie you know hydroxylamine is a reactant, you know how many electrons it looses) to write half reaction of hydroxylamine oxidation and then to take random stabs - trying to balance charge, hydrogen and oxygen with H₂O, H⁺ and OH^- and looking at possible products.