1. The problem statement, all variables and given/known data Hydroxylammonium chloride reacts with Iron(III)chloride (FeCl3) in solution to produce Iron(II)Chloride, HCL, H2O, and a compound of nitrogen. It was found that 2.0 g of iron(III) chloride reacted in this way with 31 mL of 0.200 M hydroxylammonium chloride. Suggest a possible formula of the nitrogen compound produced. This should be a known nitrogen compound 2. Relevant equations NH3OHCl + FeCl3 ----> FeCl2 + H2O + X 3. The attempt at a solution mole FeCl3 2g(1mole/162.2g) = 0.012 mole mole NH3OHCl 31.0ml(1L/1000mL)(0.2 mole/L) = 0.0062 mole FeCL3 = 0.012/0.0062 = 1.9 = 2 NH3OHCl = 0.0062/0.0062 = 1 This is the part I'm stuck at. The mol ratio is 2:1 and the compound is supposed to be N2O but I don't know how to arrive at that conclusion.