samleemc
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Ly ≡ (x +1)^2y′′− 4(x +1)y′+6y =0
given y[1]=(x+1)^2 is a solution, use the ansatz y2(x)= u(x)(x+1)2 to reduce
the order of the differential equation and find a second independent solution y2
how to reduce !? and i can't find u ...can't solve (x+1)^2u''+6u=0
please help!
thx!
given y[1]=(x+1)^2 is a solution, use the ansatz y2(x)= u(x)(x+1)2 to reduce
the order of the differential equation and find a second independent solution y2
how to reduce !? and i can't find u ...can't solve (x+1)^2u''+6u=0
please help!
thx!
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