Regression for a first order system

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SUMMARY

This discussion focuses on performing regression analysis for the diameter of a part using the equation: Diameter = -0.0531052 + 0.0443237 * exp(-0.0103633 * 'Time elapsed'). A user seeks assistance in calculating 'Time elapsed' when the diameter is -0.052. The community emphasizes the importance of solving the equation independently while providing hints, specifically mentioning the use of natural logarithms as part of the solution process.

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  • Understanding of regression analysis concepts
  • Familiarity with exponential functions
  • Knowledge of natural logarithms
  • Basic algebraic manipulation skills
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  • Study the properties of exponential functions in regression
  • Learn how to apply natural logarithms to solve equations
  • Explore regression analysis techniques in Python using libraries like NumPy and SciPy
  • Review case studies on diameter measurement in engineering applications
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Students in engineering or mathematics, data analysts performing regression analysis, and anyone interested in applying mathematical concepts to real-world problems.

Smitha921
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Homework Statement


I am carrying out a regression for diameter of a part

Homework Equations



Diameter = -0.0531052 + 0.0443237 * exp (-0.0103633 * 'Time elapsed')

if diameter is -0.052
then can some one please calculate the value for time elapsed

would you please explain the steps

The Attempt at a Solution

 
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Hello @Smitha921,

:welcome:

Welcome to PF!
Smitha921 said:

Homework Statement


I am carrying out a regression for diameter of a part

Homework Equations



Diameter = -0.0531052 + 0.0443237 * exp (-0.0103633 * 'Time elapsed')

if diameter is -0.052
then can some one please calculate the value for time elapsed

would you please explain the steps

The Attempt at a Solution


We won't do your work for you. You'll have to do that yourself.

But we will try to help you along if you get stuck.

You have an equation. Solve for t. Hint: The solution involves, in part, the natural logarithm.
 

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