Relation between a measurement and the operators

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SUMMARY

The discussion centers on the relationship between quantum measurement operators and the states they act upon, specifically examining operators M1 = |0><0| and M2 = |1><1|. It is established that a measurement must involve a complete set of operators to yield valid outcomes, as demonstrated by the probabilities PM1 = cos(a)^2 and PM2 = sin(a)^2 for the states |0> and |1>, respectively. The author argues that stating "perform operator M1 on state |p>" is misleading, as it neglects the necessity of including all relevant operators to satisfy the completeness equation. This highlights the importance of using a comprehensive set of operators in real-world quantum measurements.

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  • Basic concepts of Hermitian conjugates in quantum theory
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Now, here is the problem. (Capital letters indicate operators, lower letters are states, * indicates Hermitian conjugate)
Say we know that state | p > = cos(a) |0> + sin(a) |1> (0<a<PI, a is in R)
Two operators : M1= |0><0| , M2=|1><1|, apperatantly they satisfy the completeness equation. M1*M1+M2*M2 = I

According to some textbooks, if we perform ONE opeartor on |p>, we should have TWO outcomes |0> or |1>, with certain probabilities. Here is the details:

If I use one operator on the state, say M1,
then: the state AFTER the operation is: M1 |p> / sqrt(<p | M*M |>p) = cos(a) |0> / cos(a) = |0> ...(1)
the probability of this happening is PM1= <p | M*M |>p = cos(a)^2 ...(2)

NOW, according to (1), it is impossible to get state (outcome) |1> after the operation.
SO, where do the after-state (outcome) |1> go?
I can get the outcome of |1> only with the other operator M2.
M2 |p> / sqrt(<p | M*M |>p) = sin(a) |1> / sin(a) = |1> ...(3)
with the probability PM2=sin(a)^2.....(4)

To me, it seems that :
The language of "use operator on state |p>" is not correct.
A measurement can NOT contain ONLY a subset of the operators (in this case, contains only M1, not M2),
A measurement have to be composed of a SET of operators which satisfies completeness equation.


Is this the case in real-world experiments? We can not say "perform M1 on p", but have to say "perform the measurement which has M1 and M2 on p" or "measure the spin in the |0> to |1> axis"?

BTW, put it in another way. If we keep M1 unchanged, but change M2 to | 1/sqrt(2)( |0> - |1>) > < 1/sqrt(2)( <0| - <1|)|, (they do not satisfy the compleness equation). SO, a measurement containing ONLY M1 and M2 can not be made in real life. Is this right?
 
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I'd say that if the operator representing the quantity that you are measuring is M, and it's eigenvectors are |0> (eigenvalue = M1) and |1> (eigenvalue = M2) (and that's the complete set of eigenvectors for that operator), then for any initial state | p > = cos(a) |0> + sin(a) |1>, the projection operators acting on that state can give you the probability amplitude of a measurement of M giving any particular value (M1 or M2).
 

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