Relative Motion: Calculating the Angle for Accurate Newspaper Delivery

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SUMMARY

The discussion focuses on calculating the angle at which a newspaper boy must throw papers to accurately reach porches while riding his bicycle. The boy rides at a speed of 4m/s relative to the sidewalk and throws papers at a speed of 6m/s relative to himself. To determine the correct angle, one must apply the principles of relative motion and the Pythagorean theorem, recognizing that the throw is not purely horizontal but at an angle due to the boy's forward motion.

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  • Understanding of relative motion concepts
  • Knowledge of basic trigonometry, specifically SOH CAH TOA
  • Familiarity with the Pythagorean theorem
  • Ability to visualize motion in two dimensions
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  • Study the principles of relative velocity in physics
  • Learn how to apply the Pythagorean theorem in motion problems
  • Explore trigonometric functions in real-world applications
  • Investigate projectile motion and its calculations
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Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of relative motion in real-life scenarios.

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Homework Statement



Homework Statement


A newspaper boy throws papers sideways onto the porches of his customers while riding his bicycle along the sidewalk. The sidewalk is 15m in front of the porches. The boy throws the papers at a horizontal speed of 6m/s relative to himself, and rides the bicycle at a speed of 4m/s relative to the sidewalk.
Question: If he waits until he is directly opposite a porch, at what horizontal angle with respect to the sidewalk will he have to throw the paper to hit the porch?

Homework Equations



soh cah toa

The Attempt at a Solution


Here is the triangle I'm supposed to get, but what I don't get is why is the hypoteneuse of the triangle 6m/s, when that is the horizontal speed, shouldn't the horizontal line of the triangle be 6?

4509cb0bc1cc061483b2f9632c47e7b5.png
 
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Who said that triangle has to be like that? I also understood from the question that 6m/s should be on the X the other side, not the hyp.
And thus hypotenuse would be derived from pythagoras theorem
 
He is not throwing the newspaper straight sideways from himself, but back at an angle. Yet the speed relative to the boy is 6m/s, so that is 6m/s at the perceived angle. To a bystander, the paper does travel perpendicularly to the boy's path. (But at some other speed.)
 
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