Relative velocity with respect to image in the mirror

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SUMMARY

The discussion focuses on calculating the relative velocity between a man running towards a mirror and his image in that mirror. The man runs at a constant velocity of 7 m/s to the left, while the mirror moves to the right at 9 m/s. The correct relative velocity between the man and his image is determined to be 32 m/s, achieved by considering both the motion of the mirror and the man. The initial incorrect calculation of 23 m/s is clarified through a step-by-step analysis of the movements involved.

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Homework Statement



As shown in the figure, a man is running towards left with
constant velocity of 7 m/s. Also, a flat vertical mirror is moved
to the right with constant velocity of 9 m/s. Calculate the
relative velocity between the man and his image. Express
your answer in meter/second.

Figure -
5MUXD.png


Homework Equations





The Attempt at a Solution



Since man is running to the left with velocity 7 then the image also must move right at 7 m/s. Also since the mirror is also moving , the total velocity of the image is 16 m/s towards right. So the relative velocity between the man and image should be 16+7= 23m/s . But the answer is incorrect . Please explain.
 
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Well, think about this. If the person stands still and the mirror moves at 9 m/s how fast does the image move. Then add the fact that the man also moves at 7 m/s, what is the net result?

Here is another approach. Draw an initial diagram with the man say 1 meter in front of the mirror and then look at where the image is. Then move the man to the left 7 meters and the mirror to the right 9 meters and recalculate where the image is. What do you get?
 
Last edited:
barryj said:
Well, think about this. If the person stands still and the mirror moves at 9 m/s how fast does the image move. Then add the fact that the man also moves at 7 m/s, what is the net result?

Here is another approach. Draw an initial diagram with the man say 1 meter in front of the mirror and then look at where the image is. Then move the man to the left 7 meters and the mirror to the right 9 meters and recalculate where the image is. What do you get?
Thanks a lot ! I got it. The answer is 32 m/s.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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