Relativistic acceleration transformation

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SUMMARY

The discussion focuses on the relativistic acceleration transformation for a rocket ship accelerating at a constant rate of 1g for 40 years, as observed from Earth. The key equations involved are dx'=gamma*(dx-vdt) and dt'=gamma*(dt-vdx/c^2). The user derived the relationship a'=a/(gamma^3*(1-uv/c^2)^3) but encountered a contradiction when calculating observed acceleration, suggesting a misunderstanding of the variables u and v in the context of the formulas. The conclusion emphasizes the importance of correctly interpreting these variables to resolve the apparent paradox.

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  • Knowledge of the gamma factor (γ) in relativistic physics.
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  • Learn about the Lorentz transformation equations in detail, focusing on their applications in relativistic contexts.
  • Explore the concept of relativistic velocity addition and its effects on acceleration measurements.
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pantheid
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Homework Statement


The given problem is that we have a rocket ship, accelerating at a constant rate of 1g (in its own instantaneous inertial rest frame) for 40 years. We must find the distance it travels in that time, as measured by an observer on earth.

Homework Equations


dx'=gamma*(dx-vdt)
dt'=gamma*(dt-vdx/c^2)

The Attempt at a Solution


I have derived the relationship a'=a/(gamma^3*(1-uv/c^2)^3)

Given that the rocket has constant acceleration in its own rest frame, a'=g
Given that the observer on Earth is stationary, u=0

If we use these two facts, we get that g*gamma^3=a, which is nonsensical because that means that at very high velocities, the observed acceleration is higher than g when it should be lower. Where is my error?
 
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pantheid said:
I have derived the relationship a'=a/(gamma^3*(1-uv/c^2)^3)

Given that the rocket has constant acceleration in its own rest frame, a'=g
Given that the observer on Earth is stationary, u=0
I don't believe this is the correct interpretation of u. Make sure you know the meaning of u and v in the formula.
 

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