C/C++ Resize Vector and Populate with Integers for C++ CountDown Problem

[osu3124]

Problem Statement:
Resize vector countDown to have newSize elements. Populate the vector with integers {newSize, newSize - 1, ..., 1}. Ex: If newSize = 3, then countDown = {3, 2, 1}, and the sample program outputs:
3 2 1 Go!

Code I have so far, it works but I don't understand how to populate the vectors with integers counting down.

#include <iostream>
#include <vector>
using namespace std;

int main() {
   vector<int> countDown(0);
   int newSize = 0;
   int i = 0;

   newSize = 3;
   
   countDown.resize(newSize);

   for (i = 0; i < newSize; ++i) {
      cout << countDown.at(i) << " ";
   }
   cout << "Go!" << endl;

   return 0;
}

 

[I like Serena]

Problem Statement:
Resize vector countDown to have newSize elements. Populate the vector with integers {newSize, newSize - 1, ..., 1}. Ex: If newSize = 3, then countDown = {3, 2, 1}, and the sample program outputs:
3 2 1 Go!

Code I have so far, it works but I don't understand how to populate the vectors with integers counting down.

#include <iostream>
#include <vector>
using namespace std;

int main() {
   vector<int> countDown(0);
   int newSize = 0;
   int i = 0;

   newSize = 3;
   
   countDown.resize(newSize);

   for (i = 0; i < newSize; ++i) {
      cout << countDown.at(i) << " ";
   }
   cout << "Go!" << endl;

   return 0;
}

Hi osu3124! Welcome to MHB! ;)

How about creating a for-loop to populate the vector?
Say, iterate [m]i[/m] from [m]0[/m] to [m]newSize[/m], and initialize the corresponding elements with [m]newSize - i[/m]?

 

[osu3124]

Hi osu3124! Welcome to MHB! ;)

How about creating a for-loop to populate the vector?
Say, iterate [m]i[/m] from [m]0[/m] to [m]newSize[/m], and initialize the corresponding elements with [m]newSize - i[/m]?

I got it working. Thanks so much!