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ResourcesHelp|Close Moment of a Force: Scalar Formulation

  1. Sep 16, 2010 #1
    1. The problem statement, all variables and given/known data
    A pipe is anchored to a wall at point A. During the pipe's installation, several forces are applied to the pipe at different locations. If F1 = 14.7 lb, F2 = 18.5 lb, F3 = 12.6 lb, F4 = 10.9 lb, d1 = 0.400 ft, d2 = 0.800 ft, and d3 = 0.800 ft, what is MRA, the net moment about point A due to these forces? Assume that moments acting counterclockwise about point A are positive whereas moments acting clockwise are negative.

    2. Relevant equations
    MRA = [tex]\Sigma[/tex]Fd

    3. The attempt at a solution
    MRA = F1d2 - F2d2 + F3(d3 - d1) - F4d3

    not sure about the direction (using the right-hand rule)

    Attached Files:

  2. jcsd
  3. Sep 20, 2010 #2
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