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SUMMARY

The discussion focuses on calculating the net moment about point A (MRA) for a pipe subjected to multiple forces during installation. The forces applied are F1 = 14.7 lb, F2 = 18.5 lb, F3 = 12.6 lb, and F4 = 10.9 lb, with corresponding distances d1 = 0.400 ft, d2 = 0.800 ft, and d3 = 0.800 ft. The formula used to determine MRA is MRA = F1d2 - F2d2 + F3(d3 - d1) - F4d3. The discussion also addresses the application of the right-hand rule for determining moment direction.

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Homework Statement


A pipe is anchored to a wall at point A. During the pipe's installation, several forces are applied to the pipe at different locations. If F1 = 14.7 lb, F2 = 18.5 lb, F3 = 12.6 lb, F4 = 10.9 lb, d1 = 0.400 ft, d2 = 0.800 ft, and d3 = 0.800 ft, what is MRA, the net moment about point A due to these forces? Assume that moments acting counterclockwise about point A are positive whereas moments acting clockwise are negative.

Homework Equations


MRA = [tex]\Sigma[/tex]Fd

The Attempt at a Solution


MRA = F1d2 - F2d2 + F3(d3 - d1) - F4d3

not sure about the direction (using the right-hand rule)
 

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