Reversing the Definition of Limit: Does the Error Alter its Meaning?

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Discussion Overview

The discussion revolves around the implications of reversing the definition of a limit in calculus. Participants explore whether this alteration affects the meaning of the limit concept, focusing on the definitions involving epsilon and delta.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant questions if reversing the limit definition changes its meaning, presenting the original and altered definitions for consideration.
  • Another participant asserts that the change does affect the meaning and prompts further explanation.
  • A subsequent reply requests clarification on how the altered definition impacts the original.
  • A later contribution provides a specific example using the function f(x) = 1, suggesting that it satisfies the reversed definition but not the original, indicating a potential discrepancy in meaning.

Areas of Agreement / Disagreement

Participants do not reach a consensus; there are differing views on whether the reversal of the limit definition changes its meaning, with some arguing it does and others seeking clarification.

lith101
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so i have a question. If you reverse the definition of limit, does the error change the meaning?

original: for each epsilon>0, there exists a delta>0, such that if 0<|x-c|<delta, then |f(x)-L|<epsilon.

with an error: for each delta>0, there exists an epsilon>0, such that if 0<|x-c|<delta, then |f(x)-L|<epsilon.

So does this error change the meaning of the definition? thanks
 
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Yes, it does. Do you see how?
 
no, please explain
 
Consider the function f(x) = 1 for all x, c=0, L=2 (and not L=1 as you would expect). Show that this satisfies the new definition, but not the original one.
 

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