# Riemann's zeta function fractal because of Voronin?

1. Dec 12, 2012

### nomadreid

Riemann's zeta function "fractal" because of Voronin?

I am not sure which rubric this belongs to, but since the zeta function is involved, I am putting it here.
I noticed a comment (but was in too much of a hurry to remember the source) that, because of the "universality" of the Riemann zeta function as expressed in the Voronin Theorem, that the zeta function was in some form "fractal". I do not understand what aspect of fractals was being invoked in that comment, since the function does not fit the classic definition of a fractal as far as I can see. Any clues? Thanks.

2. Feb 2, 2015

3. Feb 4, 2015

### nomadreid

Many thanks, Churnhouse!

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