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Rotational acceleration on merry go round

  1. Jun 23, 2007 #1
    The rotational velocity of a merry go round increases at a constant rate from 0.6rad/s to 1.8rad/s in a time of four seconds. What is the rotational acceleration of the merry go round?

    This is what i have done so far but not too sure


    Time = 4seconds
    Change in velocity = 1.8rad/s – 0.6rad/s
    = 1.2rad/s
    Acceleration = ∆ω/t
    = 1.2rad/s/4seconds
    Answer = 0.3rad/s2
     
  2. jcsd
  3. Jun 23, 2007 #2
    As far as I can tell, everything is correct.
     
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