Rotational acceleration on merry go round

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SUMMARY

The rotational acceleration of a merry go round is calculated as 0.3 rad/s². This value is derived from the change in rotational velocity, which increases from 0.6 rad/s to 1.8 rad/s over a period of four seconds. The formula used for this calculation is acceleration (α) = Δω/t, where Δω is the change in velocity and t is the time interval. The calculations presented confirm the accuracy of this result.

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mike2007
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The rotational velocity of a merry go round increases at a constant rate from 0.6rad/s to 1.8rad/s in a time of four seconds. What is the rotational acceleration of the merry go round?

This is what i have done so far but not too sure


Time = 4seconds
Change in velocity = 1.8rad/s – 0.6rad/s
= 1.2rad/s
Acceleration = ∆ω/t
= 1.2rad/s/4seconds
Answer = 0.3rad/s2
 
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As far as I can tell, everything is correct.
 

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