Rotational Equilibrium: Finding Force at Point B and D

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Homework Help Overview

The discussion revolves around a problem related to rotational equilibrium, specifically focusing on calculating forces at points B and D while considering the torques involved. Participants are exploring the implications of net torque being zero in a system with applied forces.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the effects of forces at points B and D on the rotational motion of a hinged block. Questions are raised about the direction of torque caused by these forces and the appropriate lengths of the lever arms involved in the torque calculations.

Discussion Status

There is an ongoing exploration of the relationships between forces and torques, with some participants confirming each other's reasoning. Guidance has been offered regarding the definitions of torque and lever arms, contributing to a deeper understanding of the problem.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for discussion. The focus is on understanding the setup and implications of rotational equilibrium without reaching a definitive conclusion.

reder
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Hello I've attached the problem. Any help would be greatly appreciated.



I understand that by giving us the clue of rotational equilibrium, it means net T has to be 0. The force at 10N will cause clockwise torque (T= rF, so T = .04m * 10N). The thing that confuses me is the force at point B, will it cause counterwise torque or no torque? Also I know the force that we are finding at point D will give us counterclockwise torque, but is the moment arm or lever arm going to be .04m too?

Thank You.
 

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Hi reder! Welcome to PF! :smile:

reder said:
I understand that by giving us the clue of rotational equilibrium, it means net T has to be 0.

You're right there!

The thing that confuses me is the force at point B, will it cause counterwise torque or no torque?
Think about a situation of such a hinged block, and you applying adequate force to it at the lower end(B). Would it rotate? If yes, which way?

but is the moment arm or lever arm going to be .04m too?
By definition, torque about a point is the force multiplied by the perpendicular distance between the line of action of force and the point. What does that tell you about the lever arm length? :wink:
 


Think about a situation of such a hinged block, and you applying adequate force to it at the lower end(B). Would it rotate? If yes, which way?
My guess would be, it would rotate counterclockwise.

By definition, torque about a point is the force multiplied by the perpendicular distance between the line of action of force and the point. What does that tell you about the lever arm length? :wink:[/QUOTE]
So I can just extend the line of action of force at point D and this in turn would make it the lever arm .04m.

So if I am taking clockwise as negative torque and counterclockwise as positive torque... - -.04(10N) + (5N) (.02) + (F) (.04)= 0
.4 = .1+ .04F
F = 7.5N...(Is my reasoning correct)...
Also thanks for a quick reply...
 


reder said:
My guess would be, it would rotate counterclockwise.

Right-o!


So if I am taking clockwise as negative torque and counterclockwise as positive torque... - -.04(10N) + (5N) (.02) + (F) (.04)= 0
.4 = .1+ .04F
F = 7.5N...(Is my reasoning correct)...

Absolutely.
 


Thx infinitum for the help...
 

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