Same method not working in 2 age problems

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Homework Help Overview

The discussion revolves around two age-related problems involving algebraic equations. The first problem concerns the ages of Lindsay and Kimberly, while the second focuses on Tiffany's age in relation to future ages. Participants are exploring the formulation of equations based on the wording of the problems.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the setup of equations for both problems, questioning the correctness of the initial attempts. There is a focus on how the wording of the problems may lead to different interpretations and equations.

Discussion Status

Some participants have provided guidance on correcting the equations, particularly for Tiffany's age problem. There is an ongoing exploration of the implications of the equations and the definitions of variables, with some participants expressing uncertainty about their solutions.

Contextual Notes

Participants are navigating the constraints of the problem statements and the assumptions inherent in age-related algebraic problems. There is mention of potential confusion arising from similar wording in the two questions.

zak100
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Homework Statement



Q1. Lindsay is twice as old as she was 10 years ago. Kimberly is half as old as she will be in 10 years.

Find Lindsay’s age now?

Find Kimberly’s age now?

Q2.
In 8 years Tiffany will be 3 times as old as she is now. The number of years until Tiffany will be 6 times as old as she is now.

Homework Equations


Simple algebric equation of one variable

The Attempt at a Solution


Q1 Solution:
Let L = Lindsay’s age & K = Kimberly’s age

L=2(L-10)=>L=20

K=1/2(K+10)=>k=10

Q2 Solution:
T = 3(T+8)

But this is not correct. Some body guide me. The wordings of two questions are same but why same technique not working.Zulfi.
 
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zak100 said:
Q2 Solution:
T = 3(T+8)
How are you defining T here? Age now?
 
zak100 said:
Q2 Solution:
T = 3(T+8)

But this is not correct.
Because your equation is wrong.
Your equation says that Tiffany's age now is equal to 3 times her age in 8 years. That can't be true. People's ages normally get larger, not smaller.
 
Hi,

I am able to find out the correct equation. The correct equation is:

T+8 = 3T

The complete question is:

In 8 years Tiffany will be 3 times as old as she is now. The number of years until Tiffany will be 6 times as old as she is now. Find out the number of years until Tiffany will be 6 times as old as she is now.My solution is:

T+8 = 3T =>2T = 8 => T =4

6 times = 6 * 4= 24

Therefore number of years until Tiffany will be 6 times as old as she is now = 24-20 =20

Please tell me if its right or wrong.Zulfi.
 
zak100 said:
Please tell me if its right or wrong.
It's right.
 
zak100 said:
Q2.
In 8 years Tiffany will be 3 times as old as she is now. The number of years until Tiffany will be 6 times as old as she is now.

zak100 said:
My solution is:

T+8 = 3T =>2T = 8 => T =4
So, in the language of the problem, Tiffany's age right now is 4.
zak100 said:
6 times = 6 * 4= 24

Therefore number of years until Tiffany will be 6 times as old as she is now = 24-20 =20

Please tell me if its right or wrong.
There's no need to ask us to confirm whether your answer is correct or not. You should get in the habit of checking your answers. If you start out by defining your variables clearly, then it makes it easier to write correct equations as well as to check your solutions.

In this problem, Tiffany's age now is 4. How old will she be in 8 years? Will her age then be three times her age now? In 20 years how old will she be? Will her age by six times what it is now?
 

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