Scaling Problem in Diffusion Equation

Click For Summary
SUMMARY

The discussion centers on the scaling of the diffusion equation, specifically how the function f(η) behaves under the transformation where η = x/√t. It is established that after scaling, the diffusion equation transforms into an ordinary differential equation (ODE), which encapsulates all possible solutions for pairs of x and t in terms of η. The participants clarify that while f(η) is invariant with respect to the scaling parameters, the partial derivatives ∂f/∂x and ∂f/∂t are not zero, indicating that f(η) retains dependence on x and t through η.

PREREQUISITES
  • Understanding of partial differential equations (PDEs)
  • Familiarity with ordinary differential equations (ODEs)
  • Knowledge of scaling transformations in mathematical physics
  • Basic concepts of diffusion processes
NEXT STEPS
  • Study the derivation of the diffusion equation and its solutions
  • Explore scaling methods in PDEs and their implications
  • Learn about the physical interpretations of solutions to the diffusion equation
  • Investigate the role of boundary conditions in diffusion problems
USEFUL FOR

Mathematicians, physicists, and engineers interested in the mathematical modeling of diffusion processes and those seeking to deepen their understanding of scaling techniques in differential equations.

kayahan
Messages
1
Reaction score
0
Hello everyone,

I have a question that is bothering me a bit. I would be happy if you could give an idea or tell me a specific point to look at.

Lets say that we have an arbitrary function that obeys diffusion equation:

f = f(η), here η is the scaling parameter for pde which equals to x/√t
(Diffusion eq. becomes [itex]df/d\eta=-2\eta d^{2}f/d\eta^{2}[/itex] after scaling)

As I understood, diffusion eq. becomes an ode after scaling and it contains all the possible solutions for x and t pairs in η. Can we say that f(η) is invariant with respect to x and t? or in other words say ∂f/∂t=0 or not? What kind of physical information can we get just by lloking at f(η)?

Thanks in advance!
 
Physics news on Phys.org
No, [itex]\partial f/\partial x[/itex] and [itex]\partial f/\partial x[/itex] are NOT 0 because [itex]\eta[/itex] is itself a function of x and t.

[tex]\frac{\partial f}{\partial x}= \frac{df}{d\eta}\frac{\partial \eta}{\partial x}= \frac{1}{\sqrt{t}}\frac{df}{d\eta}[/tex]
[tex]\frac{\partial f}{\partial t}= \frac{df}{d\eta}\frac{\partial \eta}{\partial t}= -\frac{x}{\sqrt{t^3}}\frac{df}{d\eta}[/tex]
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 0 ·
Replies
0
Views
4K