Second derivative of effective potential

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SUMMARY

The discussion focuses on determining the value of r in terms of l, k, and m for the function V(r) = -(k/r) + (l^2/(2mr^2)), which represents an effective potential. Participants emphasize the necessity of calculating the first and second derivatives of V(r) to find the minimum and confirm its nature. The second derivative test is crucial for proving that the identified point is indeed a minimum. Additionally, the conversation touches on deriving Kepler's third law from Kepler's second law, indicating a broader context of physics applications.

PREREQUISITES
  • Understanding of calculus, specifically derivatives
  • Familiarity with effective potential in classical mechanics
  • Knowledge of Kepler's laws of planetary motion
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the process of finding critical points using first and second derivatives
  • Learn about effective potential and its applications in classical mechanics
  • Explore the derivation of Kepler's third law from Kepler's second law
  • Practice derivative calculations, particularly for power functions
USEFUL FOR

Students in physics, particularly those struggling with calculus and its applications in mechanics, as well as anyone interested in the mathematical foundations of celestial mechanics.

dswatson
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Determine the value of r in terms of l, k, and m for which the following function has a minimum.

V(r) = -(k/r) + (l^2/(2mr^2))

where l, k, and m are positive constants.

Prove that this is a minimum by showing that the second derivative of V(r) at the minimum is positive.

I have no idea how to even begin this...I am horrible at derivatives and am struggling in my physics class with them. Any help would be greatly appreciated.

I am then asked to derive Kepler's third law from Kepler's second law. So I feel I have a lot of work ahead of me.
 
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Then practice derivates!

Try this one:

what is the derivative with respect to x in this function: [tex]f(x) = x^a[/tex], where a is a real number, (non zero).

That is all you need for this particlar problem :-)
 

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