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Second order pde - on invariant?

  1. Jan 25, 2013 #1
    second order pde -- on invariant?

    What the meaning for a second order pde is rotation invariant?
    Is all second order pde are rotation invariant? or only laplacian?
     
  2. jcsd
  3. Jan 25, 2013 #2

    Simon Bridge

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    Re: second order pde -- on invariant?

    Well, do you know what "rotation invarient" means to start with?
    It sounds like you've come across the terms as part of a course involving laplacians - in which case, you were shown a proof somewhere that the laplacian is rotation invarient. What was the condition the laplacian had to satisfy for the proof to work? Do all 2ndO PDEs satisfy this condition?
     
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