Separation energy of nucleons and Coulomb barrier

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SUMMARY

The discussion centers on the separation energy of nucleons, specifically highlighting that emitted nucleons are primarily neutrons due to their lower separation energy compared to protons. The Coulomb barrier, a result of the repulsive force between protons, complicates the separation of protons from the nucleus, contrary to initial expectations that repulsion would ease separation. The professor's explanation involves considering the process in reverse, emphasizing energy conservation and the implications for beta decay stability, particularly in the context of isotopes like ##^{60}_{27}##Co and ##^{60}_{28}##Ni.

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  • Understanding of nuclear physics concepts, particularly nucleon separation energy
  • Familiarity with Coulomb's law and its implications in nuclear interactions
  • Knowledge of beta decay processes and conservation of energy in nuclear reactions
  • Basic grasp of nuclear structure and the role of protons and neutrons
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  • Research the concept of separation energy in nuclear physics
  • Study the Coulomb barrier and its effects on nucleon emission
  • Examine beta decay mechanisms and their energy considerations
  • Explore the role of nuclear forces in nucleon interactions and stability
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ValeForce46
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Why is a neutron easier to extract than a proton? It should be the other way around because Coulomb force is repulsive and the only attractive force in the nucleus is the strong force.
My professor and the book I'm reading (Particles and Nuclei: An Introduction to the Physical Concepts by Povh et al.) says that "The emitted nucleons are primarily neutrons since they are not hindered by the Coulomb threshold" which means that a neutron has a separation energy lower than a proton. They take this as true, indeed for example when a nucleus decays to another nucleus in an excited state, we compare the energy of this excited level and the separation energy of neutron to check if it's bonded for nucleons' emission (like in the ##\beta##-decay
##^{60}_{27}##Co ##\to## ##^{60}_{28}##Ni).

I still don't get how, although the Coulomb force between protons is repulsive, the existence of this force makes it harder to separate a proton from a nucleus. I'd expect the proton to see something which reduce the confinement inside the well (of the nucleus) but this is not the true, it sees a barrier caused by this force. Instead a neutron doesn't see a barrier because there's no Coulomb force and therefore (I guess?) it's easier to separate.

So, why the Coulomb force, which should facilitate the separation as it's repulsive, makes it harder for a proton to be separated than a neutron?

However, my professor gives an explanation which I really hate (or maybe I don't understand?). She says that to understand this, you have to see the process in time-reverse, which means the proton that "enters" the nucleus and of course it meets a barrier. Then something about conservation of the energy in the reverse process and that's it.
 
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If isotopes are stable against beta decays then p -> n + e+ has to be forbidden. In that reaction we would gain energy from the positron leaving the nucleus, that means the highest filled proton energy level has to be lower than the highest filled neutron energy level, otherwise you would get beta+ decays. How much lower is given by the Coulomb potential.
 

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