Why do we need to equate the rate of energy of the second plate to zero?

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The discussion centers on the necessity of equating the rate of energy of the second plate to zero in the context of thermal equilibrium. The equation derived, $$dq_{2}/dt = A \sigma ((373)^4/2 + (273)^4/2 - T_{2}^4)$$, illustrates the conservation of energy principle, specifically in radiation flux. The participants clarify that for thermal equilibrium, the outgoing energy must equal the incoming energy, which is essential to maintain a constant temperature, T2. The concept of a black body with a transmission coefficient of τ = 0 reinforces the need for this equality in energy flux.

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First i computed the rate of energy wrt time of the second plate:
$$dq_{2}/dt = A \sigma ((373)^4/2 + (273)^4/2 - T_{2}^4)$$
Equaliting it to zero we get the answer. But i am not sure why do we need to equality it to zero.
The q arrow on the figure suggest me that it is conservation of energy (radiation flux), but i don't get why.
The black body has transmission coefficient ##\tau = 0##, so i don't understand why the flux of radiation need to be equal. The body could pretty well absorb the energy coming from 1 and emite an energy to 3 totally different, couldn't?
 
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For thermal equilibrium, outgoing =ingoing. If that were not true, the temperature ##T_2## would change
 
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hutchphd said:
For thermal equilibrium, outgoing =ingoing. If that were not true, the temperature ##T_2## would change
Yes i imagined it, but as the questions says nothing about equilibrium, i discarded the possibility. But since you pointed it too, i think that's enough to close this topic.
 

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