Set Theory: Proving D has 2^d Subsets of Cardinality d

[Punkyc7]

Let D be a set that has cardinality d WTS that D has 2$^{d}$ subsets of cardinal number d.


So I was thinking about slitting D into two sets C$_{1}$ and C$_{2}$ both of cardinality d. From there I think that there are d$^{d}$ subsets that contain C$_{1}$. Since d is an infinite cardinal d$^{d}$=2$^{d}$.

Does that work or am I missing something>

 

[HallsofIvy]

I have no idea what your question is. What does 'WTS' mean? And what are you trying to do?

 

[Punkyc7]

want to show what I said I want to show. Were is the confusion?