Set Theory: Proving D has 2^d Subsets of Cardinality d

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SUMMARY

The discussion centers on proving that a set D with cardinality d has 2^d subsets of cardinality d. The user proposes splitting D into two subsets, C1 and C2, each with cardinality d, leading to the conclusion that there are d^d subsets containing C1. The user asserts that since d is an infinite cardinal, d^d equals 2^d, establishing the desired result. The conversation highlights the importance of understanding cardinality and the implications of infinite sets in set theory.

PREREQUISITES
  • Understanding of cardinality in set theory
  • Familiarity with infinite sets and their properties
  • Knowledge of basic set operations and subsets
  • Concept of exponentiation in the context of cardinal numbers
NEXT STEPS
  • Study the properties of infinite cardinal numbers
  • Explore the concept of power sets and their cardinalities
  • Learn about Cantor's theorem and its implications for set theory
  • Investigate the relationship between cardinality and set partitions
USEFUL FOR

Mathematicians, students of set theory, and anyone interested in the foundations of mathematics and the properties of infinite sets.

Punkyc7
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Let D be a set that has cardinality d WTS that D has 2[itex]^{d}[/itex] subsets of cardinal number d.


So I was thinking about slitting D into two sets C[itex]_{1}[/itex] and C[itex]_{2}[/itex] both of cardinality d. From there I think that there are d[itex]^{d}[/itex] subsets that contain C[itex]_{1}[/itex]. Since d is an infinite cardinal d[itex]^{d}[/itex]=2[itex]^{d}[/itex].

Does that work or am I missing something>
 
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I have no idea what your question is. What does 'WTS' mean? And what are you trying to do?
 
want to show what I said I want to show. Were is the confusion?
 

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