Shielding Effect and Chemical Shift

Click For Summary
SUMMARY

The discussion focuses on the chemical shifts of hydrogen atoms in chloroethene (vinyl chloride, ClCH=CH2) due to the influence of electronegativity and electron density. It concludes that the hydrogen atom on the Cl-CH= bond experiences the greatest deshielding, resulting in the largest chemical shift, followed by the cis-position hydrogen, and finally the trans-position hydrogen, which is the least affected. The concept of deshielding is emphasized, highlighting that halogens like chlorine withdraw electron density from adjacent carbons, affecting the shielding of hydrogen atoms.

PREREQUISITES
  • Understanding of chemical shifts in NMR spectroscopy
  • Knowledge of electronegativity and its effects on electron density
  • Familiarity with the concept of shielding and deshielding in molecular structures
  • Basic knowledge of chloroethene (vinyl chloride) structure and bonding
NEXT STEPS
  • Study the principles of NMR spectroscopy and chemical shift calculations
  • Research the effects of electronegativity on molecular electron density
  • Explore the concept of shielding and deshielding in more complex organic molecules
  • Examine case studies of chemical shifts in halogenated compounds
USEFUL FOR

Chemistry students, organic chemists, and researchers interested in NMR spectroscopy and the effects of electronegativity on molecular behavior.

edimeo25
Messages
5
Reaction score
0

Homework Statement


Given a molecule of chloroethene (vinyl chloride) or ClCH=CH2. Rank the hydrogen atoms in the molecule in terms of which will have the greatest chemical shift.


Homework Equations


None


The Attempt at a Solution


Since the Cl and the double bond are both electron-rich, this affects the shielding of each proton. So to rank them, I think it could go one of two ways:
1) The proton on the Cl-CH= is the most blinded (smallest chemical shift) since it is between the two electron-rich groups, followed by the proton in the cis position to the Cl since it is slightly closer to the electronic density than the H in the trans position to the Cl.
OR
2) The reverse order so: the H on the Cl-CH= is the least blinded (largest chemical shift) because the Cl is electronegative and is withdrawing the electron density from the H. Then the H in the cis position to the Cl would be 2nd rank in terms of blinding and then followed by the H in the trans position to the Cl (being the least blinded) because all of its electron density is being pulled toward the double bond and the Cl.

I think I'm a bit mixed up on how electronegativity works, so any help would be greatly appreciated. Thanks in advance!
 
Physics news on Phys.org
edimeo25 said:

The Attempt at a Solution


Since the Cl and the double bond are both electron-rich, this affects the shielding of each proton. So to rank them, I think it could go one of two ways:
1) The proton on the Cl-CH= is the most blinded (smallest chemical shift) since it is between the two electron-rich groups, followed by the proton in the cis position to the Cl since it is slightly closer to the electronic density than the H in the trans position to the Cl.
OR
No. Halogens are electron rich relative to a similar carbon group but they get that way in part because they withdraw electron density from the carbon they are attached to. Therefore, the remaining carbon is electron-deficient so the geminal C-H bond is polarized with more electron density being pulled toward the carbon. This effect is called de-shielding.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K