MHB Show all real roots are negative

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The discussion centers on proving that all real roots of the polynomial f(x) = x^5 - 10x + 38 are negative. Participants explore different approaches to the problem, emphasizing the importance of diverse methods for learning. One participant questions the implications of rewriting the function in a specific form and its relation to the domain. The conversation highlights the collaborative nature of problem-solving in mathematics. Ultimately, the focus remains on demonstrating the negativity of the roots.
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Show that all real roots of the polynomial $f(x)=x^5-10x+38$ are negative.

Note:

I know this is a fairly easy challenge, but it's good to see how different approaches can be generated from different people so that we can learn from one another. :o (Yes)
 
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anemone said:
Show that all real roots of the polynomial $f(x)=x^5-10x+38$ are negative.

Note:

I know this is a fairly easy challenge, but it's good to see how different approaches can be generated from different people so that we can learn from one another. :o (Yes)

$f(x)= x^5 + 10(3.8-x) $
it is >0 for $0\le x\lt3.8$

further
$f(x) = x(x^4-10) + 38$

for $x\gt 2$ above is > 0 as $2^4 = 16 \gt 10$

so above is >0 for $2\le x$

we have shown that it is positive for x > 0 so no root 0 or positive hence all real roots are -ve.
 
Last edited:
kaliprasad said:
$f(x)= x^5 + 10(3.8-x) $
it is >0 for $0\le x\lt3.8$

further
$f(x) = x(x^4-10) + 38$

for $x\gt 2$ above is > 0 as $2^4 = 16 \gt 10$

so above is >0 for $2\le x$

we have shown that it is positive for x > 0 so no root 0 or positive hence all real roots are -ve.

Hi kaliprasad,

Thanks for participating.:) I am curious, is there any chance when you rewritten the function of $f$ as $f(x) = x(x^4-10) + 38$, you mean to imply the domain when $x\ge 10^{\tiny\dfrac{1}{4}}$?
 
anemone said:
Hi kaliprasad,

Thanks for participating.:) I am curious, is there any chance when you rewritten the function of $f$ as $f(x) = x(x^4-10) + 38$, you mean to imply the domain when $x\ge 10^{\tiny\dfrac{1}{4}}$?

You are right but I have shown that it is true for x < 3.8 from the 1st equation and I have chosen a suitable value < 3.8 ( that is 2) to show that it is true for x > 2. $x\ge 10^{\tiny\dfrac{1}{4}}$ condition is a superset of it. but if it is true for x > 2 it does meet the criteria
 
kaliprasad said:
You are right but I have shown that it is true for x < 3.8 from the 1st equation and I have chosen a suitable value < 3.8 ( that is 2) to show that it is true for x > 2. $x\ge 10^{\tiny\dfrac{1}{4}}$ condition is a superset of it. but if it is true for x > 2 it does meet the criteria

Oh My...I don't know what is wrong with me! How could I ask something so stupid! Sorry kali, I so wish to retract what I have asked just to appeared to be less silly...:o
 
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