Is the He2+ Ion Bound Using the Simple MO Method?

  • Thread starter Thread starter Oskar Paulsson
  • Start date Start date
  • Tags Tags
    Bound Helium Ion
Click For Summary
SUMMARY

The discussion centers on demonstrating that the He2+ ion is bound using the simple Molecular Orbital (MO) method. The Hamiltonian for the system is defined as H=-(ħ2/2m)∇2 -2ke2[∑3i=11/riB+∑3i=11/riB-2/RAB]. The total wave function is proposed as ψ = 1/√(2+2S)[φa+φb], indicating a bound state. The participant explores the implications of the Pauli principle and suggests a total wave function that incorporates superposition, but seeks further mathematical resources for a more rigorous understanding.

PREREQUISITES
  • Understanding of Molecular Orbital Theory
  • Familiarity with the Pauli Exclusion Principle
  • Knowledge of quantum mechanics and wave functions
  • Basic proficiency in Hamiltonian mechanics
NEXT STEPS
  • Study the derivation of the Hamiltonian for multi-electron systems
  • Learn about the implications of the Pauli Exclusion Principle in quantum chemistry
  • Investigate the mathematical formulation of antisymmetric wave functions
  • Explore advanced resources on Molecular Orbital Theory and its applications
USEFUL FOR

Students and researchers in quantum chemistry, particularly those focusing on molecular bonding and wave function analysis in multi-electron systems.

Oskar Paulsson
Messages
4
Reaction score
0

Homework Statement


"Use the simple MO method to show that the He2+ ion is bound"

Homework Equations


The hamiltonian for this system is;

H=-(ħ2/2m)∇2 -2ke2[∑3i=11/riB+∑3i=11/riB-2/RAB]

And as far as I know, the total wave function sould be;

ψ = φ1φ2φ3 ... φn , n is the number of electrons and "a reasonable behaviour" for an electron would look like this;

φ= caφa + cbφb

in the course literature they explain this as reasonable for one electron in a diatomic molecule because this one electron is "a little bit influenced by a and a little bit by b".

The a's and b's is for each atom/nuclei.

A bound state has the total wave function:

ψ = 1/√(2+2S)[φab]

The Attempt at a Solution


So far the only 'attempts' I've made at solving this has been pretty much speculation - firstly I'm considering the Pauli principle. From the perspective of the Pauli principle we should have 1 electron in the 1sa orbital and 2 in the 1sb which is equivalent with 2 1sa + 1 1sb.

So the total wavefunction, I speculate to be some thing like;

ψ = ca1sa + cb1sb + 1/√(2)*(ca1sa + cb1sb)

The first term should be an electron which has a b-term that is almost 0 and the next one should be for an electron with an a-term that is almost 0. The third term is for an electron in "superposition" between 1s2a and 1s2b.

So - how to proceed? I am headed in the right direction? Does anyone have a source for some solid math on this whole thing because the course literature isn't very theoretical, it just shows some results and doesn't bother to properly explain anything.
 
Physics news on Phys.org
The total wave function has to be antisymmetric, but as far as I remember, your approach, while not physically possible, leads to the same energy if you evaluate that. You can compare this energy to the unbound state.
 

Similar threads

Replies
5
Views
11K
  • · Replies 1 ·
Replies
1
Views
4K