Show that three new found nuclei are unstable

[Taylor_1989]

Homework Statement

Question: Three new nuclei are claimed to have been discovered:

$\left(i\right)\:^{26}_9F\:,\:\left(ii\right)\:^{63}_{32}Ge,\:\left(iii\right)^{94}_{47}Ag$

For each nucleus, what about it enables you to say it must be unstable

Homework Equations

The Attempt at a Solution

My answers
i) A large difference between the neutron and proton. For the size of the atomic number this would be above the neutron drip line.

Now is there anything in the SEMF that I can use to verify this as maybe the pauli exculsion principle as surely a high number of proton to neutrons would show a big reduction in the binding energy? Or I was thinking when you take the derivative of the SEMF and findhing the minimum it can be show that for small values of A that Z=A/2 and for large value of A<A/2 and for heave values but I am not really sure what you can define as a small number would you say 26 is a small A value?

ii) This is unstable due to the slightly higher proton to neutron. This would result in a higher Columbus repulsion.

iii) the odd-odd nature of the number of proton to neutron indicates the unstable nature as, there are only five 4 which are in the very low end <10 and 1 which is in the very high end >100

Do these answers seem reasonable, or is there more I could add or remove?

 

[drvrm]

the third nucleus lies at Z =N line but the stability curve is far away from this line.
see
https://www.quora.com/What-determines-the-stability-of-a-nucleus