PeterDonis said:
Please show this explicitly, or give a reference that does so. It does not seem at all obvious to me, but I'm not very familiar with the concepts you're using.
For "my fixed version of" Demystifier's simplified scenario, L was defined as
gentzen said:
L |neutral_L, neutral_R⟩ = 0
L |ionized_L, neutral_R⟩ = |ionized_L, neutral_R⟩
L |neutral_L, ionized_R⟩ = |neutral_L, ionized_R⟩
L |ionized_L, ionized_R⟩ = 0
The "more mundane measurement operators" would just measure a single classical state. For example, an operator M_{iL,nR} could be defined via
M_{iL,nR} |neutral_L, neutral_R⟩ = 0
M_{iL,nR} |ionized_L, neutral_R⟩ = |ionized_L, neutral_R⟩
M_{iL,nR} |neutral_L, ionized_R⟩ = 0
M_{iL,nR} |ionized_L, ionized_R⟩ = 0
M_{iL,nR} measures, whether the state of the chamber is such that the left atom is ionized and the right atom is still neutral.
M_{iL,nR} commutes with L, i.e. L M_{iL,nR} = M_{iL,nR} L, because there exists a basis of shared eigenstates. And if I would define similar operators M_{nL,nR}, M_{iL,iR}, and M_{nL,iR}, similar statements would apply to them.
In conclusion, measuring L doesn't put up any restriction for talk about what would have happened if M_{iL,nR} or any of the other mundane measurements operators would have been measured. (Well, consistent histories doesn't say "would have been measured", but is just concerned with talk about the state as if it had the measurable properties.)