Significance of ((H,x),x) double commutator?

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SUMMARY

The discussion focuses on the significance of the double commutator ((H,x),x) in quantum mechanics, specifically for the Hamiltonian H = p^2/2m + V. It highlights the role of double and higher-order commutators in transformations such as rotations and translations, which are generated by unitary transformations U defined as U = e^{iA}. The transformation of operators in Hilbert space is shown to be invariant under these transformations, with the Taylor series expansion revealing the importance of higher-order commutators in determining transformation properties. The double commutator is particularly relevant for calculating changes in the Hamiltonian when transitioning to a moving reference frame.

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Peeter
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I've just done a textbook exersize to calculate (H,x) and ((H,x),x) for H= p^2/2m +V.

Having done the manipulation, my next question is what is the significance of this calculation. Where would one use these commutator and double commutator relations?
 
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One place where the double (and higher) commutator comes into play is when you perform a transformation, such as a rotation or a translation.

Transformations such as these are performed through a unitary transformation [tex]U[/tex]. In turn, such a unitary transformation is said to be generated by the Hermitian operator [tex]A[/tex] if we can write:

[tex]U = e^{iA}[/tex]

Here the exponential of an operator is defined through the Taylor series of the exponential. Now, the effect of this transformation is that it transforms vectors in your Hilbert space as:

[tex]|v\rangle \longrightarrow |v'\rangle = e^{iA}|v\rangle[/tex]

Operators which act on this Hilbert space are also transformed, namely:

[tex]O \longrightarrow O' = U^\dagOU = e^{-iA}Oe^{iA}[/tex]

With this definition the expecation value of the operator [tex]O[/tex] is invariant under the transformation, i.e.

[tex]\langle v|O|v\rangle \langle v'|O'|v'\rangle[/tex]

Anyways, if you expand the transformation of the operator, i.e. if you just use the Taylor series, you will find that it looks like:

[tex]e^{iA}Oe^{-iA} = O + i[O,A] + \frac{i^2}{2!} [[O,A],A] + \ldots[/tex]

where the dots denote the triple and higher commutators.

Long story short, the higher order commutators of two operators determine the transformation properties of one operator with respect to the transformation generated by the other operator.
 
Adding to the above:

[tex]mx[/tex] is the generator of the Galilean boost (see e.g. "http://www.physics.princeton.edu/~mcdonald/examples/QM/brown_ajp_67_204_99.pdf" "). So if you want to calculate how H changes when you change your reference frame to a moving one with velocity v, you will have to calculate the double commutator. (The higher commutators will be easy in this particular case!)
 
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