- #1

Vibhor

- 971

- 40

## Homework Statement

We measure the period of oscillation of a simple pendulum .In successive measurements ,the readings turn out to be 2.63 s , 2.56s , 2.42s , 2.71s and 2.80s . What is the period of oscillation taking into account appropriate significant figures ?

## Homework Equations

## The Attempt at a Solution

Mean period of oscillation T = ( 2.63 + 2.56 + 2.42 + 2.71 + 2.80 ) / 5 = 13.12/5 =2.62s

Arithmetic mean of absolute error ΔT = ( 0.01 + 0.06 + 0.20 + 0.09 + 0.18 ) /5 =0.11 s

This gives time period = 2.62 ± 0.11s

But , since the arithmetic mean is 0.11 s there is already an error in the tenth of a second . Hence there is no point in giving the period to a hundredth .

Now , my doubt is whether time period should be expressed as (2.62 ± 0.11s) OR (2.6 ± 0.1s) .

Thanks