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Simple Algebra problem - Solving for 2 of the same unknown

  1. Dec 5, 2012 #1
    1. The problem statement, all variables and given/known data

    ln(0.0693/0.0475) = (70435/8.314)((T3-298)/(T3*298))

    Solve for T3



    2. Relevant equations



    3. The attempt at a solution

    The fact that there are 2 T3's is really throwing me off, I feel that I am doing something algebraically wrong.

    0.377 = 8471.9((T3-298)/(T3*298))

    How would I solve for T3?
     
  2. jcsd
  3. Dec 5, 2012 #2

    SammyS

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    [itex]\displaystyle \frac{T_3-298}{298T_3}=\frac{T_3}{298T_3}-\frac{298}{298T_3}[/itex]
    [itex]\displaystyle =\frac{1}{298}-\frac{1}{T_3}[/itex]​
    Now there's only one T3 .
     
  4. Dec 5, 2012 #3
    Sometimes I find "getting rid" of the fraction helpful for seeing the solution. Basically multiply both sides by the denominator (of the RHS) and expand. Then you collect like terms and everything else is easy.
     
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