Simple Algebra problem - Solving for 2 of the same unknown

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The discussion focuses on solving the equation ln(0.0693/0.0475) = (70435/8.314)((T3-298)/(T3*298)) for the variable T3. The user initially struggles with the presence of two T3 variables in the equation. The solution involves simplifying the equation to isolate T3 by eliminating fractions, leading to a single T3 variable. The final steps include multiplying both sides by the denominator and collecting like terms to arrive at the solution.

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Homework Statement



ln(0.0693/0.0475) = (70435/8.314)((T3-298)/(T3*298))

Solve for T3



Homework Equations





The Attempt at a Solution



The fact that there are 2 T3's is really throwing me off, I feel that I am doing something algebraically wrong.

0.377 = 8471.9((T3-298)/(T3*298))

How would I solve for T3?
 
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smaan said:

Homework Statement



ln(0.0693/0.0475) = (70435/8.314)((T3-298)/(T3*298))

Solve for T3

Homework Equations



The Attempt at a Solution



The fact that there are 2 T3's is really throwing me off, I feel that I am doing something algebraically wrong.

0.377 = 8471.9((T3-298)/(T3*298))

How would I solve for T3?
\displaystyle \frac{T_3-298}{298T_3}=\frac{T_3}{298T_3}-\frac{298}{298T_3}
\displaystyle =\frac{1}{298}-\frac{1}{T_3}​
Now there's only one T3 .
 
Sometimes I find "getting rid" of the fraction helpful for seeing the solution. Basically multiply both sides by the denominator (of the RHS) and expand. Then you collect like terms and everything else is easy.
 

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