1. The problem statement, all variables and given/known data Three point charges are located at the corners of an equilateral triangle as shown in Figure P15.13 (q = 3.00 µC, L = 0.400 m). Calculate the net electric force on the 7.00 µC charge. ° (counterclockwise from the +x axis) http://www.webassign.net/pse/p23-07alt.gif 3. The attempt at a solution F_12 = 8.9875 x 10^9 (3e-6)(7e-6)/.4e2 = 1.18 N F_13 = 8.9875e9 (7e-6)(4e-6)/.4e2 = 1.57 N then F_12x = 1.18cos60 = .59 N F_12y = 1.18sin60 = 1.0219 N F_13x = 1.57cos60 = .785 N F_12y = -1.57sin60 = -1.3697 N then i added them up Fx = .59 + .785 = 1.375 N Fy = -1.3597 + 1.0219 = - .3378 N I know that to get the degree its arctan Fy/Fx but i get the incorrect answer. Is there something wrong in the equation or im i using the wrong number? I understand how to do the first part which is 1.4 N of electric force on 7uC charge. Thanks for any help.