Simple harmonic motion: find amplitude given k, x, v, and a

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jdp1991
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Homework Statement



A block attached to a spring is experiencing simple harmonic motion. You know the value of postion, velocity, and acceleration at an unknown time. Find the period of oscillation, the mass of the block, and the amplitude of oscillation.

We were given values for k, x, v, a

Homework Equations


F=ma=kx
Tspring=2∏√(m/k)
x=Acos(ωt+phi)

The Attempt at a Solution


This was the final question on an exam I just took and I was baffled about how to find Amplitude. We were given values for position, velocity, and acceleration, but I cannot remember what they were off the top of my head, so an algebraic solution is fine.

I started my finding the mass of the block by setting kx=ma: m=kx/a

I then plugged that value for m into the spring period equation: T=2∏√((kx/a)/k)=2∏√(x/a)

The previous two I'm not confident about, but I was completely lost when asked to find the amplitude.

Thanks

EDIT: The problem takes place on a horizontal plane (a flat frictionless surface)
 
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How are velocity and acceleration related to the position?
 
Is this on a horizontal or vertical plane?
 
SammyS said:
How are velocity and acceleration related to the position?

velocity = dx/dt and acceleration = d2x/dt2?
So v = -ωAsin(ωt+phi)
and a = -ω2Acos(ωt+phi)

Villyer said:
Is this on a horizontal or vertical plane?

Sorry horizontal
 
So, a/x = -ω2 . Gives you ω.

Then x2 + (v/ω)2 = A2
 
SammyS said:
So, a/x = -ω2 . Gives you ω.

ok that makes sense

SammyS said:
Then x2 + (v/ω)2 = A2

maybe I'm missing something obvious, but how did you get this?
 
jdp1991 said:
EDIT: The problem takes place on a vertical plane

jdp1991 said:
Sorry horizontal

Still a little lost :3
 
Villyer said:
Still a little lost :3

OOPS! Haha sorry it should be horizontal.
 
SammyS said:
So, a/x = -ω2 . Gives you ω.

Then x2 + (v/ω)2 = A2

jdp1991 said:
ok that makes sense

maybe I'm missing something obvious, but how did you get this?
Did you try it.

sin2(θ) + cos2(θ) = 1