The problem involves calculating the total cent value of a set of 20 coins consisting of nickels and dimes, with a given ratio of 2:3. The equations derived from the problem are 2x = 3y and x + y = 20, where x represents the number of nickels and y represents the number of dimes. Solving these equations reveals that there are 8 dimes and 12 nickels, leading to a total value of 60 cents from the nickels and 80 cents from the dimes, resulting in a total cent value of 140 cents for the 20-coin set.
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Ognerok said:Homework Statement
Aggregate # of nickels and dimes = 20 coins. If the ratio between nickels and dimes is 2:3, what is cent value of 20-coin set?
Homework Equations
2x = 3y
The Attempt at a Solution
20 = nickels(x)+dimes(y); ratio = 2x:3y; 2x = 3y; y = 2x/3
20 = x + 2x/3; x = 12 nickels; 6 dimes? ...confused from there.