Now if I have a function y=(ab+ac)/a, it can be further factorised, y=(a(b+c))/a. Now if we cancel off the a, we will have only y=b+c that will also give the same y-values as the original form of the function y with respect to the same x-value. This statement implies that cancellation or simplification of a rational function is NOT SIGNIFICANT. However, when we let the y-value equal to 0, for the simplified form,y=b+c, we have only one solution, (b+c)=0. For the original form, y=(a(b+c))/a, we can have 2 solutions ,(a)(b+c)=0,so (a)=0 or (b+c)=0. This shows that simplification of a function is SIGNIFICANT! Moreover, when we have a function, y=((x+1))/((x+1)(x-1)). Apparently, we can see that this rational polynomial function have 2 vertical asymptotes: x=1 and x=-1 in which at this line, the y-value is undefined! Now if we simplify the function to y=1/(x-1), when x=-1,y=-1/2 which is a definite value! So , is that simplification of a function is significant or not significant??