Simplify sin(A) + sin(A + 2π/3) + sin(A + 4π/3)

  • Context:
  • Thread starter Thread starter Silver Bolt
  • Start date Start date
  • Tags Tags
    Identity
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
Silver Bolt
Messages
8
Reaction score
0
$\sin\left({A}\right)+\sin\left({A+\frac{2\pi}{3}}\right)+\sin\left({A+\frac{4\pi}{3}}\right)=0$

$L.H.S=\sin\left({A}\right)+\left(\sin\left({A}\right)\cos\left({\frac{2\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{2\pi}{3}}\right)\right)+\left(\sin\left({A}\right)\cos\left({\frac{4\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{4\pi}{3}}\right)\right) $

From there?
 
Last edited:
Mathematics news on Phys.org
You've only given an expression...what is the actual identity to be verified?
 
Silver Bolt said:
$\sin\left({A}\right)+\sin\left({A+\frac{2\pi}{3}}\right)+\sin\left({A+\frac{4\pi}{3}}\right)=0$

$L.H.S=\sin\left({A}\right)+\left(\sin\left({A}\right)\cos\left({\frac{2\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{2\pi}{3}}\right)\right)+\left(\sin\left({A}\right)\cos\left({\frac{4\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{4\pi}{3}}\right)\right) $

From there?

I would write the LHS as:

$$\sin(A)\left(1+\cos\left(\frac{2\pi}{3}\right)+\cos\left(\frac{4\pi}{3}\right)\right)+\cos(A)\left(\sin\left(\frac{2\pi}{3}\right)+\sin\left(\frac{4\pi}{3}\right)\right)$$

Now, what are:

$$1+\cos\left(\frac{2\pi}{3}\right)+\cos\left(\frac{4\pi}{3}\right)=?$$

$$\sin\left(\frac{2\pi}{3}\right)+\sin\left(\frac{4\pi}{3}\right)=?$$