Simplifying (√18 + √12) / (√8 - √96) in terms of p and q

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p = root 2 q = root 3
(root 18 + root 12) / (root 8 - root 96) , write this in terms of p and q in its simplest form. I keep getting the wrong answer, please help! :confused:
 
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Post your working, so people can show you where you've gone wrong.
 
dextercioby said:
Do you know how to decompose natural numbers into prime factors...??

Daniel.
yes, but i don't end up with the answer i was meant to!
 
Gughanath said:
p = root 2 q = root 3
(root 18 + root 12) / (root 8 - root 96) , write this in terms of p and q in its simplest form. I keep getting the wrong answer, please help! :confused:
[tex]p = \sqrt{2}[/tex] , [tex]q = \sqrt{3}[/tex]

[tex]\frac{(\sqrt{18} + \sqrt{12})}{(\sqrt{8} - \sqrt{96})}[/tex]

Personally I just try to make the numbers with the smallest number of terms possible.

E.g. [tex]\sqrt{18} = \sqrt{3 \times 3 \times 2} = pqq[/tex] or [tex]p2q[/tex] or [tex]\sqrt{18} = 3 \sqrt{2} = 3p[/tex]

The Bob (2004 ©)
 
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You have twice said you "keep getting the wrong answer". Tell us what wrong answers you get and how you are trying to do the problem!