Simultaneous differential equation

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SUMMARY

The discussion centers on solving the simultaneous differential equation given by the relationships \(\frac{dx}{y+z} = \frac{dy}{x+z} = \frac{dz}{x+y}\). The solution provided in the referenced book is \(\sqrt{x+y+z} = \frac{a}{z-y} = \frac{b}{x-z}\). Participants suggest that substitution methods may be effective, but initial attempts with substitutions such as \(u=x+y\), \(u=x+z\), \(u=y+z\), and \(u=x+y+z\) did not yield successful results.

PREREQUISITES
  • Understanding of simultaneous differential equations
  • Familiarity with substitution methods in differential equations
  • Knowledge of algebraic manipulation and simplification techniques
  • Basic calculus concepts, particularly differentiation
NEXT STEPS
  • Research advanced techniques for solving simultaneous differential equations
  • Explore substitution methods specifically for nonlinear differential equations
  • Study the implications of the solution \(\sqrt{x+y+z} = \frac{a}{z-y} = \frac{b}{x-z}\)
  • Investigate numerical methods for approximating solutions to complex differential equations
USEFUL FOR

Mathematicians, engineering students, and anyone involved in solving complex differential equations will benefit from this discussion.

ForMyThunder
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I have this book that gives the following differential equation:

[tex]\frac{dx}{y+z}[/tex] = [tex]\frac{dy}{x+z}[/tex] = [tex]\frac{dz}{x+z}[/tex]

Could anyone give any suggestions on how to solve this? Thanks.

By the way, the book gives the answer as:

[tex]\sqrt{x+y+z}[/tex] = [tex]\frac{a}{z-y}[/tex] = [tex]\frac{b}{x-z}[/tex]

I think that there should be some kind of substitution, but all I could think of was u=x+y, u=x+z, u=y+z, and u=x+y+z. All of them came up short.
 
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Wait, the actual differential equation is:

[tex]\frac{dx}{y+z}[/tex] = [tex]\frac{dy}{x+z}[/tex] = [tex]\frac{dz}{x+y}[/tex]
 

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