1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Solution check for pH of Strong Acid and Strong Base

  1. May 3, 2009 #1
    1. The problem statement, all variables and given/known data
    Calculate the pH after 24 mL of 1.00 M NaOH is added from the burette to a beaker containing 25.0 mL of 1.00 M HCl


    2. Relevant equations
    pH = -log [H+]
    1*10^-14 = [H+][OH-]


    3. The attempt at a solution

    combined volume = 49mL

    n.unreacted(H+) = 0.025-0.024 = 0.001 mol

    [H+] = n/V = 0.001/0.049 = 0.02 mol L-1

    pH = -log[H+] = 1.69 (2 d.p)



    is that correct?

    many thanks,
    pavadrin
     
  2. jcsd
  3. May 3, 2009 #2

    symbolipoint

    User Avatar
    Homework Helper
    Education Advisor
    Gold Member

  4. May 3, 2009 #3
    okay thank you for the reply
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Solution check for pH of Strong Acid and Strong Base
Loading...