MHB Solve 2^3x+1=32: Find X Using Logs

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To solve the equation 2^(3x+1) = 32, first confirm that it is correctly interpreted as 2^(3x+1) rather than 2^(3x) + 1. The equation simplifies to 2^(3x+1) = 2^5, leading to the equality 3x + 1 = 5. By subtracting 1 from both sides, the equation becomes 3x = 4. Dividing both sides by 3 results in x = 4/3.
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hi could anyone show me the steps for solving this equation
i thought it was to be solved by logs
find X if 2^3x+1=32
 
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blackfriars said:
hi could anyone show me the steps for solving this equation
i thought it was to be solved by logs
find X if 2^3x+1=32

Is the equation:

$$2^{3x}+1=32$$

Or:

$$2^{3x+1}=32$$

I suspect it is the latter, but I want to be sure first. :)
 
the answer i got for X was 5 just by using algebra
yes it is the latter equation
thanks
 
$$2^{3x+1}=32=2^5$$

$$3x+1=5\implies x=\frac43$$
 
Could you show steps for solving for x
Thanks

- - - Updated - - -

Yeah i got it now cheers mate
 
$$3x+1=5$$

Subtract $1$ from both sides:

$$3x+1-1=5-1$$

$$3x=4$$

Divide both sides by $3$:

$$x=\frac43$$
 
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