Solve 2^3x+1=32: Find X Using Logs

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Discussion Overview

The discussion revolves around solving the equation \(2^{3x+1}=32\) using logarithms and algebraic methods. Participants explore the correct interpretation of the equation and share their approaches to finding the value of \(x\).

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant requests steps for solving the equation and suggests that logarithms may be involved.
  • Another participant seeks clarification on whether the equation is \(2^{3x}+1=32\) or \(2^{3x+1}=32\), expressing a preference for the latter.
  • A participant claims to have found \(x=5\) using algebra, confirming the latter equation.
  • Subsequent posts provide a step-by-step solution leading to \(x=\frac{4}{3}\) from the equation \(3x+1=5\).
  • One participant expresses gratitude after understanding the solution process.

Areas of Agreement / Disagreement

Participants generally agree on the interpretation of the equation as \(2^{3x+1}=32\) and the resulting solution of \(x=\frac{4}{3}\). However, there is an initial uncertainty regarding the equation's form.

Contextual Notes

Some participants initially misinterpret the equation, leading to different proposed solutions. The discussion reflects a progression from confusion to clarity as steps are shared.

Who May Find This Useful

Readers interested in algebraic methods for solving exponential equations or those looking for examples of step-by-step problem-solving in mathematics.

blackfriars
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hi could anyone show me the steps for solving this equation
i thought it was to be solved by logs
find X if 2^3x+1=32
 
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blackfriars said:
hi could anyone show me the steps for solving this equation
i thought it was to be solved by logs
find X if 2^3x+1=32

Is the equation:

$$2^{3x}+1=32$$

Or:

$$2^{3x+1}=32$$

I suspect it is the latter, but I want to be sure first. :)
 
the answer i got for X was 5 just by using algebra
yes it is the latter equation
thanks
 
$$2^{3x+1}=32=2^5$$

$$3x+1=5\implies x=\frac43$$
 
Could you show steps for solving for x
Thanks

- - - Updated - - -

Yeah i got it now cheers mate
 
$$3x+1=5$$

Subtract $1$ from both sides:

$$3x+1-1=5-1$$

$$3x=4$$

Divide both sides by $3$:

$$x=\frac43$$
 

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