MHB Solve 2^3x+1=32: Find X Using Logs

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To solve the equation 2^(3x+1) = 32, first confirm that it is correctly interpreted as 2^(3x+1) rather than 2^(3x) + 1. The equation simplifies to 2^(3x+1) = 2^5, leading to the equality 3x + 1 = 5. By subtracting 1 from both sides, the equation becomes 3x = 4. Dividing both sides by 3 results in x = 4/3.
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hi could anyone show me the steps for solving this equation
i thought it was to be solved by logs
find X if 2^3x+1=32
 
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blackfriars said:
hi could anyone show me the steps for solving this equation
i thought it was to be solved by logs
find X if 2^3x+1=32

Is the equation:

$$2^{3x}+1=32$$

Or:

$$2^{3x+1}=32$$

I suspect it is the latter, but I want to be sure first. :)
 
the answer i got for X was 5 just by using algebra
yes it is the latter equation
thanks
 
$$2^{3x+1}=32=2^5$$

$$3x+1=5\implies x=\frac43$$
 
Could you show steps for solving for x
Thanks

- - - Updated - - -

Yeah i got it now cheers mate
 
$$3x+1=5$$

Subtract $1$ from both sides:

$$3x+1-1=5-1$$

$$3x=4$$

Divide both sides by $3$:

$$x=\frac43$$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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