Solve a Quick Math Question: How Many Sides in a Polygon w/ 119 Diagonals?

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d=n^2 - 3n / 2

where d = number of diagonals
and n = the number of sides of the polygon.

A polygon has 119 diagonals, how many sides does it have?

119 = n^2 - 3n / 2

I am not sure how to do this? can someone please help?

sorry this isn't physics related
 
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An n-sided polygon has this many diagonals:

[tex]\frac{n(n-3)}{2}[/tex]

Solve for [tex]n[/tex].
 
get_rekd said:
d=n^2 - 3n / 2

where d = number of diagonals
and n = the number of sides of the polygon.

A polygon has 119 diagonals, how many sides does it have?

119 = n^2 - 3n / 2

I am not sure how to do this? can someone please help?

sorry this isn't physics related
Quadratic Formula
 

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