Solve A(x) ∆F[f]/∆f + J(x)F[f] = 0

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The discussion revolves around solving the differential equation A(x) ∆F[f]/∆f + J(x)F[f] = 0, where F is a functional of f(x), and J(x) and A(x) are known functions. Participants clarify that f must depend on x for the equation to hold, and they emphasize that F is a functional, not a standard function. The conversation suggests that substituting a series solution could be a viable approach if F were a function. The complexity arises from the nature of F as a functional, which complicates the solution process. Overall, the thread highlights the challenges in solving the equation due to the functional dependency.
Karlisbad
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Differential equation??

Let be F a functional of f(x) and J(x) and A(x) a function, then can we solve this?:

A(x)\frac{\delta F[f]}{\delta f}+J(x)F[f]=0

J and A are known functions and F[f] is an unknown functional satisfying the equation above.:confused: :confused:
 
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does f have to depend on x?
 
and are you sure you don't mean F(x)? becaue then all you need to do is substitute in a series solution.
 
F is a functional (a function of function :-p ) you introduce any function f(x) inside F and you get a number.. if F were a function i would know how to solve it...:redface:
 

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