Solve Algebraic Equation: x⁴+y⁴+z⁴-xyz(x+y+z)

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The discussion centers on the factorization of the algebraic expression $x^4+y^4+z^4-xyz(x+y+z)$. Initially, a user posted an incorrect problem statement but later clarified that the goal is to find the sum of square factorization for the expression. The correct approach involves recognizing the structure of the polynomial and applying algebraic identities to simplify it effectively.

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Factorize $x^4+y^4+z^4-xyz(x+y+z)$.
 
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anemone said:
Factorize $x^4+y^4+z^4-xyz(x+y+z)$.

is the question correct (that is I am missing something)

$x^4+y^4+z^4-xyz(x+y+z) = x^4-x^2yz - xyz(y+z) + y^4+z^4$ if we put in descending power of x and $y^4+z^4$ does not factor over real coefficients
 
kaliprasad said:
is the question correct (that is I am missing something)

$x^4+y^4+z^4-xyz(x+y+z) = x^4-x^2yz - xyz(y+z) + y^4+z^4$ if we put in descending power of x and $y^4+z^4$ does not factor over real coefficients

Ops...it was my mistake to post an incorrect problem...the problem should read:

Find the sum of square factorization for $x^4+y^4+z^4-xyz(x+y+z)$.

Sorry for causing the confusion, folks!:o
 
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