A horizontal uniform board of weight 125N and length 4m is supported by vertical chains at the ends. A person weighing 500N is sitting on the board. The tension in the right chain is 250N.
How far from the left chain is the person sitting?
The Attempt at a Solution
Well I've calculated that the left chain has a tension of 375N as to be able to hold the person-board system in equilibrium. But now they want to know how far the person is from the left chain. I know this requires the balancing of torque, but I'm not sure how.
Thanks for helping out!