Solve Circular Motion Homework: Find Tension 1 & 2

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SUMMARY

The discussion focuses on solving a circular motion homework problem involving two strings and a mass m attached to a vertical shaft. The tangential velocity of the mass is given as 3.10 m/s. The acceleration was calculated as 2.48 m/s², leading to a force of 4.34 N. The equations of motion were set up using components, with the tension in the strings represented as T1 and T2, and the angles specified as 30 degrees.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Knowledge of trigonometric functions in physics
  • Familiarity with Newton's second law of motion
  • Ability to resolve forces into components
NEXT STEPS
  • Study the principles of circular motion and centripetal acceleration
  • Learn how to apply Newton's laws to multi-body systems
  • Explore the use of trigonometric identities in force resolution
  • Practice solving tension problems in circular motion scenarios
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This discussion is beneficial for physics students, educators, and anyone involved in solving mechanics problems related to circular motion and tension forces in strings.

joemama69
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Homework Statement



A shaft is set up in the vertical direction. Two strings are attached to a mass m, the shaft is rotates so that the tangential velocity of m is 3.10 m/s

a) Find tension of string 1 & 2

Homework Equations





The Attempt at a Solution



First I found the acceleration

a = v2/r = 3.12/1.25 = 2.48 m/s2

Fa = ma = 1.75*2.48 = 4.34 N

I then took it into components

[tex]\sum[/tex]Fx = Fa - T1sin[tex]\theta[/tex] - T2sin[tex]\theta[/tex] = 0 = 4.34 - T1sin[tex]30[/tex] - T2sin[tex]30[/tex]


[tex]\sum[/tex]Fy = T1cos30 - mgT2cos30 = 0

are these correct i would just solve for the Ts here on after
 

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i thin Fy = T1 - T2 - mgcos30 = 0
 

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