Solve DE: (y-1)e^y = [(x^2+1)^(3/2)]/3 + C

[Growl]

Given that y' = [x(x^2+1)^1/2]/ye^y
How do you find solve the differential equation?
I got through some parts but have hard time solving for y when i got
(y-1)e^y = [(x^2+1)^(3/2)]/3 + C

Thanks a lot :)

 

[Office_Shredder]

It looks like you did a bit of a botch job on integrating the RHS.

\int x^3 + xdx = x^4/4 + x^2/2

I don't think you can really go much farther than you have.

EDIT: It looks right now. I would probably just hand it in as is, because I don't see a way to solve that

 

[Growl]

My bad, it's actually y' = [x(x^2+1)^1/2]/ye^y, ;), posted the problem up wrong...

Thanks anyway!

 

[CPL.Luke]

if you want to give your professor something, you can isolate x in that problem, although you'll have a plus or minus in the solution..