Solve Equation C for F: Simple Algebra

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SUMMARY

The equation C=ABF^E - AgF^(E+1) can be solved for F by rearranging it into the standard form F^(E+1) - (B/g)F^E + C/(Ag) = 0. When E is a non-negative integer, this represents an algebraic equation of degree E+1, yielding E+1 solutions. Conversely, if E is a negative integer, the equation transforms into one involving 1/F, resulting in -E solutions. While a closed-form solution is generally unattainable, numerical methods such as Newton's method can be employed to approximate the roots.

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roldy
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How do I go about solving the following equation in terms of F?

[tex]C=ABF^E-AgF^{E+1}[/tex], where C, A, B, E represent other equations not dependent on F
 
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C=ABF^E - AgF^(E+1)
F^(E+1) - (B/g)F^E + C/(Ag) = 0

If E is a non-negative integer, then this is an algebraic equation of degree E+1 and in general has E+1 solutions.
If E is a negative integer, then this is basically an algebraic equation in 1/F and of degree -E with -E solutions.
In general this equation is not solvable in closed form but you can probably obtain a root using iterations or methods such as Newton's.
 

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