MHB Solve Equation: $\sqrt{1+\sqrt{1-x^2}}$

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The equation $\sqrt{1+\sqrt{1-x^2}}(\sqrt{(1+x)^3}-\sqrt{(1-x)^3})=2+\sqrt{1-x^2}$ was discussed, leading to the conclusion that the only solution is $x=\dfrac{1}{\sqrt{2}}$. The participants confirmed this result with agreement. The interaction was friendly, with expressions of gratitude and acknowledgment of correctness. This solution highlights the specific value of $x$ that satisfies the equation. The discussion effectively resolved the problem presented.
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Solve the equation $\sqrt{1+\sqrt{1-x^2}}(\sqrt{(1+x)^3}-\sqrt{(1-x)^3}=2+\sqrt{1-x^2}$.
 
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Rewriting the equation with $a = \sqrt{1+x}$ and $b = \sqrt{1-x}$:

$\sqrt{1+ab}\left ( a^3 - b^3 \right ) = 2 + ab$

$\sqrt{1+ab}\left ( a - b \right )(a^2+b^2+ab) = 2 + ab$

$\sqrt{1+ab}\left ( a - b \right ) = 1$ - because $a^2+b^2 = 2$.

Squaring yields:

$(1+ab)\left ( a^2 + b^2-2ab \right ) = 1$

or

$2(1+ab)(1-ab)= 1$

or $(ab)^2 = \frac{1}{2}$

  • hence $1-x^2 =\frac{1}{2}$ or $x = \pm\frac{1}{\sqrt{2}}$.
 
Hi lfdahl! The correct answer is $x=\dfrac{1}{\sqrt{2}}$ only. (Smile)
 
Thankyou, anemone - of course you're right!👍
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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